1.

Find the magnitude of the centripetal acceleration of a particle on the tip of a blade, ` 0 .30 ` metre in diameter, rotating at `1200` revolution per minute.

Answer» Here, ` r=0.3//2 =0.15 m, ` v(12000/(60) =200 ros`
Centripetal acceleration, `a_cromega^2 =r 4 pi^2 v^2`
` =0.15 xx 4xx (22)/7)^2 xx (20)^2 = 2370.6 ms^(-2)`.


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