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Find the magnitude of the linear acceleration of a particle moving in a circle of radius 10 cm with uniform speed completing the circle in 4s. |
Answer» The distance covered in completing the circle is `2r = 2 xx 10 cm`. The linear speed is `v = (2r)/(t) = (2 pi xx 10 cm)/(4 s) = 5 cm s^-1` The accleration is `a = (v^2)/r = ((5 pi cm s^-1)^2)/(10 cm) = 2.5 cm s^-2`. |
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