1.

Find the manitude of a charge whose electric field strength is `18 xx 10^(3) N C^(-1)` at a distance of 5 m in air .

Answer» Given Electric field strength
`€ = 18 xx 10^(3) N C^(-1)`
Distance `(r ) = 5 m`.
Charge `(q)= ?`
`E = (1)/(4piin_(0)) (q)/(r^(2)) , 18 xx 10^(3) = 9 xx 10^(9) xx (q)/((5)^(2))`,
`:. Q = 2.25 xx 10^(11)C`


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