Find the mass of 44.8 liter of ammonia gas at stp ( n=14,h=1)

1.	Find the mass of 44.8 liter of ammonia gas at stp ( n=14,h=1)
Answer» use the ideal GAS law - PV = nRT P is pressure (1 under STP), V is the volume in liters, n is the number of moles, R is the gas constant (0.082) and T the temperature in Kelvins (273 under STP). So, rearrange for n and SOLVE and you get: n=PV/RT = 144.8/(0.082273) = 2 moles. Ammonia is NH3 so the MOLECULAR weight is 17 g/mole. To get the mass, multiple the # moles times the molecular weight: 2 moles * 17 grams/mole = 34 grams

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