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Find the mass of H_2SO_4 present in 100 cm^(3) of a decimolar solution. |
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Answer» Solution :According to the molarity relation, `w =(M xx M. xx V)/1000` In the present case, `M = 1/10` (the solutioon is decimolar) `M.=98, v = 100 cm^(3)` `therefore w = (1/10 xx 98 xx 100)/1000 = 0.98 g` HENCE, the `100 cm^(3)` of the GIVEN solution CONTAIN 0.98 g of `H_(2)SO_(4)` |
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