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Find the maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils. |
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Answer» Total number of pens = 1001. Total number of pencils = 910. Maximum number of students who get the same number of pens and same number of pencils = HCF (1001, 910). Using prime factorization, 910 = 2 × 5 × 7 ×13. 1001 = 7 × 11 × 13. Hence, HCF (1001, 910) = 7 × 13 = 91 Hence, Maximum number of students who get the same number of pens (11) and same number of pencils (10) is 91. |
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