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Find the maximum or minimum values of the function. `y=9-(x-3)^(2)` |
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Answer» `y=9-(x-3)^(2) = 6x-x^(2)` `(dy)/(dx)=6-2x` For minimum or maximum value of y, `(dy)/(dx)=0` `rArr "" 6-2x=0 "" rArr "" x=3` Here `(d^(2)y)/(dx^(2))=-2` is less than zero at x=3. `y_(max)=9-(3-3)^(2)=9` |
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