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Find the maximum value of `|[1, 1, 1],[ 1, 1+sintheta,1],[ 1, 1, 1+costheta]|` |
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Answer» `D = |[1,1,1],[1,1+sintheta,1],[1,1,1+costheta]|` Applying `R_2->R_2-R_1` and `R_3->R_3-R_1` `= |[1,1,1],[0,sintheta,0],[0,0,costheta]|` `=[1(sinthetacostheta-0)-0+0] ` `=sinthetacostheta` As `sinxcosx = 1/2sin2x` `:. D=1/2sin2theta` We know maximum value of `sin2theta` will be `1`. So, maximum value of `D` will be ` = 1/2**1 = 1/2`. |
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