1.

Find the maximum value of (m//m) in the situation shown in figure so that the system remains at rest. Friction coefficient of both the contacts is `mu` , string is massless an pulley is friction less. A. `(costheta)/(sintheta-mucostheta)`B. `(sintheta)/(sintheta-mucostheta)`C. `(mucostheta)/(sintheta-mucostheta)`D. `(mu)/(sintheta-mucostheta)`

Answer» Correct Answer - D
The system is at rest `(F_(net)=0)`
For maximum `M//m` , Limiting friction will be acting on both blocks (at contact surface).
`F=Net` pulling force on the whole system
`mumg+muMgcostheta=Mgsintheta`
`Mg(sintheta-mucostheta)=mumg`
`(M)/(m)=(mu)/((sintheta-mucostheta))`


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