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Find the maximum value of the 5 sinx+12cosx |
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Answer» SOLUTION :LET `5=rcostheta, 12=rsintheta` `therefore5^2=r^2cos^2theta,12^2=r^2sin^2theta` `therefore5^2+12^2=r^2(cos^2theta+sin^2theta)=r^2` `thereforer=(sqrt25+144)=13` `therefore` themaximum value of `5 sinx+12cosx` is 13 |
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