1.

Find the maximum value of the 5 sinx+12cosx

Answer»

SOLUTION :LET `5=rcostheta, 12=rsintheta`
`therefore5^2=r^2cos^2theta,12^2=r^2sin^2theta`
`therefore5^2+12^2=r^2(cos^2theta+sin^2theta)=r^2`
`thereforer=(sqrt25+144)=13`
`therefore` themaximum value of `5 sinx+12cosx` is 13


Discussion

No Comment Found

Related InterviewSolutions