1.

Find the maximum velocity of a SHM particle having amplitude 'A' and periodic time T.

Answer»

`(4A)/(T)`
`(2A)/(T)`
`2PI SQRT((A)/(T))`
`(2 pi A)/(T)`

SOLUTION :`v_("max")= A OMEGA = (A*2pi)/(T)= (2pi A)/(T)`.


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