1.

Find the maximum wavelength of electromagnatic radiation which can creat a hole-electron pair in silicon. The band is silicon is `1.1 eV`. [Use `h = 6.6xx10^(-34) Js , c=3xx10^(8)ms^(-1), e=1.6xx10^(-19)C.`

Answer» Here, `E_(g)=0.72 eV`
`=0.72xx(1.6xx10^(-19))J`.
If `lambda` is the maximum wavelength of electromagnetic radation, which can creat a hole-electron pair in germanium, then
`E^(g)=(hc)/lambda`
or `lambda=(hc)/E^(g)=((6.62xx10^(-34))xx(3xx10^(8)))/(0.72xx1.6xx10^(-19))`
`=1.724xx10^(-6)m`


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