1.

Find the mean deviation about the mean for the following data.Marks obtained10-20   20-30    30-40    40-50    50-60   60-70   70-80   Number of students23814832

Answer»
Marks obtainedNumber of students fiMidpoints Xifi xi |xi - x|fi|xi - x|
10-20212303060
20-30325752060
30-408352801080
40-50144533000
50-608554401080
60-703651952060
70-802751503060
N = 40 = ∑f1800∑f|x1 - x|2 = 400


Bar x = (∑fixi)/N = 1800/40 = 45

MD (x) = 10.



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