Observations x: – 1, 0, 4∴ Mean x̄ = \(\frac{−1+0+4}{3}=\frac{3}{3}\) = 1Now, Σ|x – x̄| = 2 + 1 + 3 = 6∴ Mean deviation MD = \(\frac{∑|x−x¯|}n=\frac{6}{3}\) = 2
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