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InterviewSolution
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Find the mean of the quartiles `Q_(1) , Q_(2) ` and `Q_(3)` of the data 5 , 9 , 8 , 12 , 7 , 13 , 10 , 14.A. 9B. 10C. 9.5D. 11.5 |
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Answer» Correct Answer - c The increasing order of given the observations : 5 , 7 , 8 , 9 , 10 , 12 , 13 , 14 `Q_(1) = ((n)/(4))`th observation `Q_(1) = 2` nd observation `therefore Q_(1) = 7` `Q_(2)` = Mean of `((n)/(2))` th , `((n)/(2) + 1)` th observation = Mean of 4th , 5th items = `(9 + 10)/(2) = 9.5` `Q_(3) = ((3n)/(4))` th = `(3 xx (8)/(4))` th 6th observation `Q_(3) = 12` Mean of `Q_(1) , Q_(2) , Q_(3) = ( 7 + 9.5 + 12)/(3) = (28.5)/(3) = 9.5`. |
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