1.

Find the missing value.S. No.Diagonal (d1)Diagonal (d2)Area(i)19 cm16 cm(ii)26 m468 sq. m(iii)12mm180 sq. m

Answer»

(i) Given diagonal d1 = 19 cm; d2 = 16 cm 

Area of the rhombus = \(\frac{1}{2}\)(d1 x d2) sq. units = \(\frac{1}{2}\) x 19 x 16

= 152 cm2

(ii) Given diagonal d1 = 26 m; Area of the rhombus = 468 sq. m 

= \(\frac{1}{2}\)(d1 x d2) = 468; (26 x d2) = 468 x 2 

d2 = \(\frac{468\,\times\,2}{26}\) = d2 = 36 m

(iii) Given diagonal d2 = 12 mm; Area of the rhombus 

= 180 sq. m 

\(\frac{1}{2}\)(d1 x d2) = 180 

\(\frac{1}{2}\)(d1 x 12) = 180

d1 x 12 = 180 x 2 

d1 = \(\frac{180\,\times\,2}{12}\)

d1 = 30 mm 

Diagonal d1 = 30 mm

Tabulating the results we have

S. No.Diagonal (d1)Diagonal (d2)Area
(i)19 cm16 cm152 sq. cm
(ii)26 m36 cm468 sq. m
(iii)30 mm12 mm180 sq. mm


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