1.

Find the molality of a solution containing a non-volatile solute if the vapour pressure is `2%` below the vapour pressure or pure water.

Answer» Given, `P_(S) = (98)/(100)P^(@)`
Now `(P^(@)-P_(S))/(P_(S)) = (w xx M)/(m xx W)`
`= (w)/(m xx W) xx 1000 xx (M)/(1000)`
`{(P^(@) - (98)/(100).P^(@))/((98)/(100)P^(@))} = "Molality xx (18)/(1000)`
`:. Molatity={(2P^(@))/(100xx98/100P^(@))}xx1000/18=1.1334`


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