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Find the molar heat capacity in a process of a diatomic gas if it does a work of Q/4 when a heat of Q is supplied to it |
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Answer» Solution :`dU=C_(v) dT = ((5)/(2)R)dT (or) dT=(2(dU))/(5R)` from first law of THERMODYNAMICS `dU=DQ -dW = Q-(Q)/(4) = (3Q)/(4)` Now molar heat capacity `C=(dQ)/(dT) = (Q XX 5R)/( 2(dU)) = (5RQ)/(2((3Q)/(4)))=(10)/(3) R` |
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