find the molecular formula for the following compound with given percentage composition C-40% H-6.6% O-53.4% [molar mass is 90]

find the molecular formula for the following compound with given perce

1.	find the molecular formula for the following compound with given percentage composition C-40% H-6.6% O-53.4% [molar mass is 90]
Answer» By using ELEMENT percentage composition - Atomic mass - Atomic ratioCarbon ⟶40%÷12= 1240 =3.33Hydrogen ⟶6.66%÷1= 16.66 =6.66Oxygen ⟶53.34%÷16= 1640 =3.33The least atomic ratio is 3.33.For simplest ratio, we get C:H:O = 1:2:1Empirical FORMULA = CH 2 O of mass 30 g.As molar mass = 60, Molecular formula = (CH 2 O) 2 =CH 3 COOHI hope it will HELP you