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Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force. |
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Answer» F = 20 N ⊥ distance = 0.5 m Moment of force = Force x perpendicular distance of force from the point of rotation = F x ⊥ distance = 20 N × 0.5 m = 10Nm |
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