1.

Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force.

Answer»

F = 20 N           ⊥ distance = 0.5 m

Moment of force = Force x perpendicular distance of force from the point of rotation

= F x ⊥ distance

= 20 N × 0.5 m

= 10Nm



Discussion

No Comment Found