Find the moment of inertia of a hydrogen molecule about an axis passing through its center of mass and perpendicular to the interatomic axis. Given : mass of hydrogen atom 1.7 xx 10^(-27) kg and inter atomic distance is equal to 4 xx 10^(-10) m.

Find the moment of inertia of a hydrogen molecule about an axis passin

1.	Find the moment of inertia of a hydrogen molecule about an axis passing through its center of mass and perpendicular to the interatomic axis. Given : mass of hydrogen atom 1.7 xx 10^(-27) kg and inter atomic distance is equal to 4 xx 10^(-10) m.
Answer» Solution :Moment of INERTIA `I=2m(R/2)^(2)=(MR^(2))/2` `I=(1.7xx10^(-27)xx4x4xx10^(-20))/2` `=1.36xx10^(-46)KGM^(2)`