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Find the most general solution of the following (i) sin 6x=sin 4x-sin 2x (ii)sec 4x-sec 2x=2 (iii)3-2 cos theta - 4 sin theta - cos 2 theta + sin 2theta =0 (iv)2(cos theta + cos 2 theta )+ sin 2 theta (1+cos theta)=2 sin theta |
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Answer» (ii)`(2n+1)(pi)/(10),(2m+1)(pi)/(2) ` (iii)`2npi,2npi+(pi)/(2)` (IV)`2npi(pi)/(2),2npui+(pi)/(3),(2n+1)pi` |
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