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Find the nature of roots of the quadratic equation `4x^(2)-5x+3=0`. |
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Answer» The given equation is `4x^(2)-5x+3=0.` This is of the form `ax^(2)+bx+c=0,` where a=4, b=-5 and c=3. `:." "D=(b^(2)-4ac)={(-5)^(2)-4xx4xx3}=(25-48)=23lt0.` Hence, the given equation has no real roots. |
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