1.

Find the nature of the roots of the quadratic equation 3x2 – 2√6 x + 2 = 0.

Answer»

3x2 – 2√6 x + 2 = 0

Compare given equation with the general form of quadratic equation, which is ax2 + bx + c = 0

a = 3, b = – 2√6, c = 2

Using Discriminant Formula:

D = b2 – 4ac

= (– 2√6)2 – 4 x 3 x 2

= 24 – 24

= 0

Roots of equation are real and equal.



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