1.

Find the nearest integer to the cube root of each of the following. (i) 331776 (ii) 46656 (iii) 373248

Answer»

(i) 331776

603 = 216000 < 331776 < 343000 = 703 

Hence \(3\sqrt{331776}\) lies between 60 and 70. 

We do not know whether 331776 in a perfect cube or not. 

However we may sharpen the bound. 

683 = 314432, 693 = 328509 

Hence \(3\sqrt{331776}\) lies between 69 and 70 

331776 – 328509 = 3267 

343000 – 331776= 11224 

331776 in nearer to 693 

∴ The closest integer to \(3\sqrt{331776}\) is 69. 

(ii) 46656

303 = 2700 < 46656 < 64000 – 403 

\(3\sqrt{46656}\) lies between 30 and 40 we do not know whether 46656 in a perfect cube or not. 

However we may sharper the bound 

353 = 42875, 363 = 46656

∴ \(3\sqrt{46656}\) = 36

(iii) 373248

703 = 343000 < 373248 < 512000 – 803 

\(3\sqrt{373248}\) lies between 70 and 80. 

We do not know whether 373248 is a perfect cube or not. 

However we may sharpen the bound. 

713 = 357911, 723 = 373248

∴ \(3\sqrt{373248}\) = 72



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