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Find the nearest integer to the cube root of each of the following. (i) 331776 (ii) 46656 (iii) 373248 |
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Answer» (i) 331776 603 = 216000 < 331776 < 343000 = 703 Hence \(3\sqrt{331776}\) lies between 60 and 70. We do not know whether 331776 in a perfect cube or not. However we may sharpen the bound. 683 = 314432, 693 = 328509 Hence \(3\sqrt{331776}\) lies between 69 and 70 331776 – 328509 = 3267 343000 – 331776= 11224 331776 in nearer to 693 ∴ The closest integer to \(3\sqrt{331776}\) is 69. (ii) 46656 303 = 2700 < 46656 < 64000 – 403 \(3\sqrt{46656}\) lies between 30 and 40 we do not know whether 46656 in a perfect cube or not. However we may sharper the bound 353 = 42875, 363 = 46656 ∴ \(3\sqrt{46656}\) = 36 (iii) 373248 703 = 343000 < 373248 < 512000 – 803 \(3\sqrt{373248}\) lies between 70 and 80. We do not know whether 373248 is a perfect cube or not. However we may sharpen the bound. 713 = 357911, 723 = 373248 ∴ \(3\sqrt{373248}\) = 72 |
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