1.

Find the normality of oxalic and solution containing 63 g of crystalline oxalic acid in 500 ml of solution.

Answer»

Solution :WEIGHT of solute =6.3 g
GEW of solute `=(126)/(2)=6.3g`
NORMALITY, `N=(W)/(GEW) xx (100)/(V_(ML))=(6.3)/(6.3) xx (100)/(500)=0.2N`


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