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Find the number of addresses in a range if the first address is 146.102.29.0 and last address is 146.102.32.255.(a) 1028(b) 1024(c) 578(d) 512I had been asked this question in an international level competition.This is a very interesting question from IP Addressing in section Internet Protocol, Network Addressing and Transport Level Security of Cryptograph & Network Security

Answer»

Correct option is (b) 1024

Explanation: Subtract the first address from the LAST address in base 256.

The result = 0.0.3.255

Therefore, NUMBER of ADDRESSES = (3 X 256 + 255) + 1 = 1024.



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