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| 1. |
find the number of atoms of each type present in 3.42 g of cane sugar c12 h22 o11 |
| Answer» Molar mass of C12H22O11 = 342 g. Given mass = 3.42 g. No. of atoms of C = 12 × 6.022 × 10^23 × 3.42/342 = 12 × 6.022 × 10^23 × 10^-2 = 72.264 × 10^21 atoms. // Similarly, find H and O atoms also. | |