Find the number of factors of the product 5^8 * 7^5 * 2^3 which are perfect squares.(a) 47(b) 30(c) 65(d) 19The question was asked in semester exam.I need to ask this question from Counting topic in division Counting of Discrete Mathematics

Find the number of factors of the product 5^8 * 7^5 * 2^3 which are pe

1.	Find the number of factors of the product 5^8 * 7^5 * 2^3 which are perfect squares.(a) 47(b) 30(c) 65(d) 19The question was asked in semester exam.I need to ask this question from Counting topic in division Counting of Discrete Mathematics
Answer» The correct choice is (b) 30 For explanation I would say: Any factor of this NUMBER should be of the form 5^a * 7^b * 2^c. For the factor to be a PERFECT square a, b, c has to be even. a can take VALUES 0, 2, 4, 6, 8, b can take values 0, 2, 4 and c can take values 0, 2. Total number of perfect squares = 5 * 3 * 2 = 30.

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Find the number of factors of the product 5^8 * 7^5 * 2^3 which are perfect squares.(a) 47(b) 30(c) 65(d) 19The question was asked in semester exam.I need to ask this question from Counting topic in division Counting of Discrete Mathematics

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