1.

find the number of molecules of an ideal gas in a volume of`1.000cm^(3)`atSTP.

Answer» We know,
` n=(PV)/(RT) =(1 xx 1 xx 10^-3)/(0.082 xx 273)`
` = (10^-3)/(22.4) =(1)/(22400)`
No. of molecules
`=0.023 xx 10^23 xx 1/22400`
`=2.688 xx 10^-4 xx 10^23`
` =2.688 xx 10^19`


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