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Find the number of permutation of all the letters of the wordMATHEMATICS which starts with consonants only. |
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Answer» We have letters (M M), (A A), (T T),H,E,I,C,S Number of words starting with M to T `=(10!)/(2!xx2!)` `(because` Two pairs of identical letters are available) Number of words starting with T or C or S=`(10!)/(2!xx2!xx2!)` `(because` Three pairs of identical letters are available) Therefore, total number of words `=2xx(10!)/(2!xx2!)+3xx(10!)/(2!xx2!xx2!)` `=(7xx10!)/(2!xx2!xx2!)` |
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