Find the ogeo of o G uorridrod oppeG 0 G da ०५० a2(.5 - *J) [3/

1.	Find the ogeo of o G uorridrod oppeG 0 G da ०५० a2(.5 - *J) [3/“ z) asdd (L, 3)9
Answer» Now in triangle ABD area = 1/2 { 2(-2 + 5 ) - 4( -5 -3 ) -3( 3 + 2 ) } =1/2 { 23 - 4* (-8) - 3 * 5 )= 1/2{ 6 + 32 - 15}= 23/2 therefore area of triangle ABD = 23/2 unit square ------------1now area of triangle BCD area = 1/2{ -3( -2 -3 ) + 3( 3 + 5 ) + 2( -5 + 2 ) } = 1/2 { -3-5 + 38 + 2*(-3)}=1/2 { 15 + 24 - 6 }=33/2 therefore area of triangle BCD = 33/2 unit square ------------- 2 adding 1 & 2=23/2 + 33/2=( 23 + 33 )/2=56 / 2=28therefore totall area = 28 square unit

Find the ogeo of o G uorridrod oppeG 0 G da ०५० a2(.5 - *J) [3/“ z) asdd (L, 3)9

Answer»

Now in triangle ABD

area = 1/2 { 2*(-2 + 5 ) - 4( -5 -3 ) -3( 3 + 2 ) }

=1/2 { 2*3 - 4* (-8) - 3 * 5 )= 1/2{ 6 + 32 - 15}= 23/2

therefore area of triangle ABD = 23/2 unit square ------------1now area of triangle BCD

area = 1/2{ -3( -2 -3 ) + 3( 3 + 5 ) + 2( -5 + 2 ) }

= 1/2 { -3*-5 + 3*8 + 2*(-3)}=1/2 { 15 + 24 - 6 }=33/2

therefore area of triangle BCD = 33/2 unit square ------------- 2

adding 1 & 2=23/2 + 33/2=( 23 + 33 )/2=56 / 2=28therefore totall area = 28 square unit