Saved Bookmarks
| 1. |
Find the order of magnitude of the number of atom in 1cm^(3) of a solid. Given that the diameter of an atom is about 10^(-10)m |
|
Answer» Number of atoms in the SOLID `=1` atom `xx10^(-6)m^(3)//10^(-30)m^(3)=10^(24)` atoms |
|