1.

Find the order of magnitude of the number of atom in 1cm^(3) of a solid. Given that the diameter of an atom is about 10^(-10)m

Answer»


Solution :Volume of the ATOM is of the ORDER of `d^(3)`, d-diameter.
Number of atoms in the SOLID `=1` atom `xx10^(-6)m^(3)//10^(-30)m^(3)=10^(24)` atoms


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