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Find the oxidation number of the underlined atoms. Na_2underlineB_4O_7 |
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Answer» SOLUTION :`{:( Na_2underline B_4O_7,Na_2,B_4,O_7), (LET ON is ,+1,x,-2):}` `thereforei.e., (+1 times2) +( x times 4) +(-2 times7)=0 implies2+4x-14=0 IMPLIES 4x=12 implies x=+3` OXIDATION number of B in `Na_2B_4O_7` is +3. |
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