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Find the oxidation number of the underlined atoms. underlineBrF_3 |
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Answer» Solution :`{:( underlineBrF_3, UNDERLINE(BR), F_3), (Let ON is, x , (-1)):}` `THEREFORE i.e., (x times1) +(-1 TIMES3)=0 implies x-3=0 implies x=+3` Oxidation number of Br in `BrF_3` is +3. |
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