Find the oxidation state of sulphur in the following compounds: H_2S_,

1.	Find the oxidation state of sulphur in the following compounds: H_2S_,H_2SO_4,S_2O_4^(2-),S_2O_8^(2-)
Answer» Solution :In `H_2S`, +2+x=0, x=-2 In `H_2SO_4`, +2+x-8=0,x=+6 In `S_2O_4^(2-)`, 2x-8=-2, 2x=6, x=+3 In `S_2O_4^(2-)`, let ONE of S=x, then 2x+4(-8)=2 `therefore x=+3` In `S_2O_8^(2-)` , there is a peroxide LINKAGE, therefore oxidation state of S is 6 because S has six VALENCE electrons and it can from 6 COVALENT bonds.

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