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Find the perimeter of the beside rectangle whose length is 6x + y and breadth is 3x – 2y. |
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Answer» Given length of rectangle l = 6x + y breadth b = 3x – 2y Perimeter of Rectangle = 2 (l + b) = 2[(6x + y) + (3x – 2y)] = 2[6x + y + 3x – 2y] = 2[(6 + 3)x + (1 – 2)y] = 2[9x + (- 1) y] = 2[9x – 1y] = 2 × (9x) – 2 × (1y) ∴ Perimeter of rectangle = (18x – 2y) units. |
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