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Find the perimeter of the rectangle whose dimensions are zerovalues of quadratic polynomial x2-7x + 12. |
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Answer» Zeroes of x² - 7x + 12 x² - 7x + 12 x² -3x - 4x + 12 x( x - 3) - 4( x - 3) ( x - 3) ( x -4) So, sides are 3 and 4 So Perimeter = 2 × ( L + B) = 2 × ( 3 + 4) = 14 cm |
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