1.

Find the perimeter of the rectangle whose dimensions are zerovalues of quadratic polynomial x2-7x + 12.

Answer»

Zeroes of x² - 7x + 12

x² - 7x + 12

x² -3x - 4x + 12

x( x - 3) - 4( x - 3)

( x - 3) ( x -4)

So, sides are 3 and 4

So Perimeter = 2 × ( L + B)

= 2 × ( 3 + 4) = 14 cm



Discussion

No Comment Found