Find the perimeter of triangle whose sides are a + 3b, a – b and 2a

1.	Find the perimeter of triangle whose sides are a + 3b, a – b and 2a – b.
Answer» Let the sides of triangle are x = a + 3b, y = a – b and z = 2a – b Perimeter of triangle = x + y + z = (a + 3b) + (a – b) + (2a – b) = a + 3b + a – b + 2a – b = (a + a + 2a) + (3b – b – b) = (1 + 1 + 2)a + (3 – 1 – 1)b Perimeter of triangle. = (4a + b) units.

Find the perimeter of triangle whose sides are a + 3b, a – b and 2a – b.

Answer»

Let the sides of triangle are x = a + 3b,

y = a – b and z = 2a – b

Perimeter of triangle = x + y + z

= (a + 3b) + (a – b) + (2a – b)

= a + 3b + a – b + 2a – b

= (a + a + 2a) + (3b – b – b)

= (1 + 1 + 2)a + (3 – 1 – 1)b

Perimeter of triangle.

= (4a + b) units.