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Find the `pH` of (a)`10^(-3)M HNO_(3)` solution (b)`10^(-4)MH_(2)SO_(4)` solution (Take`log2=0.3`) |
Answer» `(a)p-log [H^(+)]_(HNO_(3))=-log(10^(-3))=3` `(b) pH=-log[H^(+)]_(H_(2)SO_(4))=-log(2xx10^(-4))=4-log2=3.7` In both solution,`[H^(+)]_("from strong acid") gt 10^(-6)M` so `H^(+)` from water has not been considered. |
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