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Find the point in xy-plane which is equidistant from the three points (2,0,3),(0,3,2) and (0,0,1).

Answer» Mera y ka answer wrong aa rha h<br>Book me answer h (3,2,0)<br>Wrong answer<br>Since x-coordinate of every point in yz-plane is zero. Let P (0, y, z) be a point on the yz-plane such that PA = PB = PC.Now PA = PB(0 – 2)2 + (y – 0)2 + (z – 3)2 = (0 – 0)2 + (y – 3)2 + (z – 2)2i.e. z – 3y = 0and PB = PC⇒ y2 + 9 – 6y + z2 + 4 – 4z = y2 + z2 + 1 – 2z ,i.e. 3y + z = 6 Simplifying the two equating, we get y = 1, z = 3Here, the coordinate of the point P are (0, 1, 3).


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