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Find the point of local maxima or local minima or local minima and the corresponding local maximum and minimum values of each of the following functions:f(x) = x4 - 62x2+120x+9 |
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Answer» local max. value is 68 at x = 1 and local min. values are−1647 at x = −6 and −316 at x = 5 F’(x) = 4x3 - 124x+120 = 0 ⇒ 4(x3 - 31x+30) = 0 For x = 1, the given eq is 0 x -1 is a factor, 4(x -1)(x+6)(x -5) = 0 ⇒ X = 1, -6,5 F’’(1))<0, 1 is the point of max. F’’(-6) and f ’’(5) 0, -6 and 5 are point of min. F(1) = 68 F(-6) = -1647 F(5) = -316 |
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