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Find the point on the curve y^2 - x^2 + 2x - 1 =0 where the tangent is parallel to the x - axis. |
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Answer» Solution :Given the CURVE is `y^2 - X^2 + 2xx - 1 = 0…(1)` `rArr 2Y dy/dx - 2xx + 2 = 0` `rArr dy/dx = x- 1/y` if the tangent is parallel to `x-axis then dy/dx = 0` `x - 1/y = 0 rArr x = 1` Putting x = 1 in (1) we GET `y^2 - 1 + 2 - 1 = 0 rArr y = 0` The point is (1,0). |
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