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Find the point on the hyperbola `x^2-9y^2=9`where the line `5x+12 y=9`touches it. |
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Answer» Solving `5x+12y=9 or y=(9-5x)/(12) and x^(2)-9y^(2)=9,` we have `x^(2)-9((9-5x)/(12))=9` `"or "x^(2)-(1)/(16)(9-5x)^(2)=9` `"or "16x^(2)-(25x^(2)-90x+81)=144` `"or "9x^(2)-(25x^(2)-90x+81)=144` `"or "9x^(2)-90x+225=0` `"or "x^(2)-10x+25=0` `"or "x=5` `rArr" "y=(9-25)/(12)=-(4)/(3)` So, point of contact is `(5,-(4)/(3))`. |
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