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Find the points on the curve y = x3 - 3x2 - 9x + 7 at which the tangent to the curve is parallel to the x-axis. |
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Answer» As the tangents to the curve y = x3 - 3x2 - 9x + 7 are parallel to x-axis so, dy/dx = 3x2 - 6x - 9 = 0 3(x2 - 2x - 3) = 0 x = 3,-1 Hence the required points are (3, -20) and (-1,12). |
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