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Find the points on the curve y = x3 at which the slope of the tangent is equal to the y-coordinate of the point. |
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Answer» y = x3 \(\frac{dy}{dx}\)= 3x2, Given that \(\frac{dy}{dx}\) = y = x3 ∴ 3x2 = x3 ⇒ x2 (3 – x) = 0 ⇒ x = 0 or x = 3 when x = 3, y = 33 = 27, when x = 0, y = 0 ∴ The required points are (0, 0), (3, 27). |
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