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Find the pointsof maximaor minima of f(x) =x^(2) (x-2)^(2). |
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Answer» Solution :`F(x) =x^(2) (x-2)^(2)` `f(x) =4 x(x -1) (x-2)` `f'(x) =0 ""rArr ""x=0,1,2` EXAMINING the sighchange of f'(x) HENCE x=1 is pointof maxima x=0,2 are points of minima. Note: In case of continuous functions points of maxima and minima arealternate.k |
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