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Find the position vector of a point R which divides the line segment joiningthe points `A(2,-3,4)` and `B(3,1,-2)` externally in the ratio `3:2`. |
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Answer» The position of `A` is `(2hati -3hatj + 4hatk)`. The position vector of `B` is `(3hati + hatj - 2hatk)`. Let R divide AB extenally in the ratio `3:2` . Then, position vector of R. `= ((3vecb - 2veca)/(3-2))= (3(3hati + hatj - 2hatk) - 2(2hati - 3hatj + 4hatk))/(1)` `= (5hati + 9hatj - 14 hatk)`. Hence, the position vector of R is `(5hati + 9hatj - 14hatk)`. |
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