1.

Find the position vector of a point R which divides the line segment joiningthe points `A(2,-3,4)` and `B(3,1,-2)` externally in the ratio `3:2`.

Answer» The position of `A` is `(2hati -3hatj + 4hatk)`.
The position vector of `B` is `(3hati + hatj - 2hatk)`.
Let R divide AB extenally in the ratio `3:2` .
Then, position vector of R.
`= ((3vecb - 2veca)/(3-2))= (3(3hati + hatj - 2hatk) - 2(2hati - 3hatj + 4hatk))/(1)`
`= (5hati + 9hatj - 14 hatk)`.
Hence, the position vector of R is `(5hati + 9hatj - 14hatk)`.


Discussion

No Comment Found