1.

Find the power of an electric motor, if it lifts 200 kg of water in 5 minutes from a well of 120 m depth.

Answer»

Solution :MASS of water m = 200 KG
Depth of well =HEIGHT lifted = 120 m
Time `t = 5 XX 60` sec = 300 sec
`power = ("Work done against gravitational force")/("time")`
power = `(mgh)/(t)=(200xx9.8xx120)/(5xx60)=784W.`


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