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Find the power of an electric motor, if it lifts 200 kg of water in 5 minutes from a well of 120 m depth. |
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Answer» Solution :MASS of water m = 200 KG Depth of well =HEIGHT lifted = 120 m Time `t = 5 XX 60` sec = 300 sec `power = ("Work done against gravitational force")/("time")` power = `(mgh)/(t)=(200xx9.8xx120)/(5xx60)=784W.` |
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