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Find the power of an electric motor , if it lits 200 kg of water in 5 minutes from a well of 120 m depth. |
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Answer» SOLUTION :Mass of water m = 200 kg Depth of WELL = height lifted = 120 m Time `t = 5xx60 sec = 300sec` Power `= ("Work DONE against GRAVITATIONAL force")/("time")` Power `= (mgh)/(t)=(200xx9.8xx120)/(5xx60)=784 W`. |
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